A body of mass 40 kg wants to climb up a rope hanging vertically. The rope can withstands a maximum tension of 500 N. What is the maximum acceleration with which the boy can climb rope? Tak e `g=10m//s^(2)`

Options

A. `1.5 ms^(-2)`
B. `2.0 ms^(-2)`
C. `2.5 ms^(-2)`
D. `3.0 ms^(-2)`

Answer

C

Explanation

Let a be the maximum acceleration with which the boy can climb the rope. Then, the maximum tension in the rope will be
`T_(max) = m( g+a)`
but `,T_(max) = 500 N `( Given )
`therefore 500 =40 xx (10 +a) or a= 2.5 ms^(-2)`