Two bodies of masses 4 kg and 6 kg are tied to the ends of a massless string. The string passes over a frictionless pulley. The acceleration of the system is `:`

Options

A. `(g)/(2)`
B. `(g) /(3 )`
C. `(g)/(5) `
D. `(g)/(10)`

Answer

C

Explanation

Let a be the common acceleration of the system and T be tension of the string.
The equations of motion of two bodies are
`T- 4g =4a `
`and 6g - T= 6a`
Adding (i) and (ii), we get
`2g = 10 a or a= (g)/(5)`