Two blocks of 2 kg and 1 kg are in contact on a frictionless table. If a force of 3 N is applied on 2 kg block, then the force of contact between the two blocks will be

Options

A. `0 N`
B. `1 N`
C. ` 2 N`
D. `3 N`

Answer

B

Explanation

common acceleration of the system `a=(3)/( 2+1) = 1 ms^(-2)`
Let N be the force of contact between the two block .
The free body diagram of 1 kg block is as shown in the figure

The equation of motion is `N =1 xxa = a xx 1 =1 N`
the free body diagram of 2 kg block is as shown is figure

the equation of motion is
` 3-N =2a or n=3 -2a =3-2 xx (1) =1N`