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A shell of mass 100 g moving with speed ...

A shell of mass 100 g moving with speed of 50 `m s^(-1)` along a straight line inclined at an angle `tan^(-1) ((4)/(3))` to the horizontal bursts into two pieces. The piece of mass 60 g starts moving horizontally with a speed of 50 `m s^(-1)`. The other piece moves with a speed of

A

`50 ms^(-1)` opposite to the first piece

B

100 `m s^(-1)` in vertically downward direction

C

`50 m s^(-1)` in the same direction as the first piece

D

zero (remains at rest)

Text Solution

Verified by Experts

The correct Answer is:
B
Initial moemtum
`= (100)/( 1000) xx 50 kg ms^(-1) = kg ms^(-1)`
Horizontal momentum `= 3 kg ms^(-1)`
vertical momentum `= 4 kg ms^(-1)`
the velocity of other piece of mass 40 g
` = (4 kg ms^(-1))/( 0.04 kg ) = 100 ms^(-1)`

To conserve momentum ,it should be directed vertucally downward .
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