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A cubical block rests on an inclined pla...

A cubical block rests on an inclined plane of coefficient of friction `mu =(1)/( sqrt(3))` . What should be the angle of inclination so that the block just slides down the inclined plane?

A

`30^@`

B

`60^@`

C

`45^@`

D

`90^@`

Text Solution

Verified by Experts

The correct Answer is:
A
`As tan theta = mu`
` theta = (1)/( sqrt(3))` or ` theta = tan^(-1) ((1)/( sqrt(3))) = 30^@`
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