A block released from rest from the top of a smooth inclined plane of angle `30^@` reaches the bottom in time `t_1`. The same block released from rest from the top of another smooth inclined plane of angle `60^@`, reaches the bottom in time `t_2`. If the two inclined planes have the same height, the relation between `t_1` and `t_2` is

Options

A. `(t_2 )/(t_1) =1/2`
B. `(t_2)/(t_1)=1`
C. `(t_2)/(t_1) =(1)/( sqrt(3))`
D. `(t_2)/(t_1) =2`

Answer

C

Explanation

`(t_2)/(t_1) =(1)/( sqrt(3))`