A car of mass m is moving on a level circular track of radius R. If `mu_s` represents the static friction between the road and tyres of the car, the maximum speed of the car in circular motion is given by

Options

A. `sqrt(mu_s Rg)`
B. `sqrt((Rg)/(mu_s))`
C. `sqrt((mRg)/(mu_s))`
D. `sqrt((mu_sRg))`

Answer

D

Explanation

Force of friction provides the necessary centripetal force .
` f le mu_s N =(mv^2)/(R ) , v^2 le (mu_sRN )/(m )`
`v^2 le mu_s Rg " " [ :. N= mg ]`
`or v le sqrt( mu_s Rg)`
` therefore ` The maximum speed of the car in circular motion is
`v_("max") = sqrt( mu_s Rg)`