One end of string of length / is connected to a particle of mass 'm' and the other end is connected to a small peg on a smooth horizontal table. If the particle moves in circle with speed 'v', the net force on the particle (directed towards centre) will be (T represents the tension in the string)

Options

A. `T+(mv^2)/(l)`
B. `T-(mv^2)/(l)`
C. zero
D. `T`

Answer

D

Explanation

Centripetal force `(mv^2//l) ` is provided by tension . So net force on the particle will be equal to tension T.