In a photoelectric experiment, if both the intensity and frequency of the incident light are doubled, then the saturation photoelectric current

Options

A. remains constant
B. is halved
C. is doubled
D. becomes four times

Explanation

To solve the problem regarding the effect of doubling both the intensity and frequency of incident light on the saturation photoelectric current, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Concept of Saturation Current**:
- The saturation photoelectric current is the maximum current achieved in a photoelectric experiment when all emitted photoelectrons are collected. It is also referred to as the maximum photocurrent.

2. **Identify the Relationship Between Saturation Current and Intensity**:
- The saturation current (I_s) is directly proportional to the intensity (I) of the incident light. This means that if the intensity of the light increases, the saturation current also increases proportionally.
- Mathematically, we can express this as:
\[ I_s \propto I \]

3. **Consider the Effect of Doubling Intensity**:
- If the intensity of the incident light is doubled (I becomes 2I), then the saturation current will also double:
\[ I_s' = 2I_s \]
- Here, \(I_s'\) is the new saturation current after doubling the intensity.

4. **Evaluate the Effect of Doubling Frequency**:
- The frequency (f) of the incident light affects the energy of the photons but does not affect the saturation current directly. The saturation current depends only on the number of photoelectrons emitted, which is related to the intensity of the light.
- Therefore, even if the frequency is doubled, it does not change the saturation current.

5. **Combine the Effects**:
- Since the saturation current is only affected by the intensity and not by the frequency, the new saturation current after doubling the intensity (while frequency is doubled) remains:
\[ I_s' = 2I_s \]

6. **Conclusion**:
- Thus, if both the intensity and frequency of the incident light are doubled, the saturation photoelectric current will double due to the doubling of intensity.

### Final Answer:
The saturation photoelectric current will be doubled.