Figure shows the displacement-time graphs of two simple harmonic motions I and II. From the graph it follows that

Options

A. curve I has samme frequency as that of curve II.
B. curve I has frequency twice that of curve II.
C. curve I has frequency half that of curve II
D. curve I has frequency four times that of curve II.

Answer

C

Explanation

From the graph
for curve I,
time period, `T_(1)=8s`, frequency `upsilon_(1)=(1)/(T_(1))=(1)/(8)Hz`
For curve II,
Time period, `T_(2)=4s`, frequency, `upsilon_(2)=(1)/(T_(2))=(1)/(4)Hz`
Their corresponding ratio
`(upsilon_(1))/(upsilon_(2))=(1)/(2)` or `upsilon_(1)=(1)/(2)upsilon_(2)`.