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A particle executing SHM with time perio...

A particle executing SHM with time period T and amplitude A. The mean velocity of the particle averaged over quarter oscillation, is

A

`(A)/(4T)`

B

`(2A)/(T)`

C

`(3A)/(T)`

D

`(4A)/(T)`

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The correct Answer is:
To find the mean velocity of a particle executing Simple Harmonic Motion (SHM) averaged over a quarter of its oscillation, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Motion**: The displacement of a particle in SHM can be described by the equation: \[ x(t) = A \sin(\omega t) \] where \(A\) is the amplitude and \(\omega\) is the angular frequency. 2. **Find the Velocity**: The velocity \(v(t)\) is the derivative of displacement with respect to time: \[ v(t) = \frac{dx}{dt} = \frac{d}{dt}(A \sin(\omega t)) = A \omega \cos(\omega t) \] 3. **Determine the Time for Quarter Oscillation**: The time period \(T\) of the oscillation is related to the angular frequency by: \[ \omega = \frac{2\pi}{T} \] For a quarter oscillation, the time interval is: \[ \text{Quarter time} = \frac{T}{4} \] 4. **Calculate Mean Velocity**: The mean velocity \(v_{mean}\) over the time interval from \(0\) to \(\frac{T}{4}\) is given by: \[ v_{mean} = \frac{1}{\frac{T}{4}} \int_0^{\frac{T}{4}} v(t) \, dt \] Substituting the expression for velocity: \[ v_{mean} = \frac{4}{T} \int_0^{\frac{T}{4}} A \omega \cos(\omega t) \, dt \] 5. **Integrate the Velocity Function**: The integral of \(\cos(\omega t)\) is: \[ \int \cos(\omega t) \, dt = \frac{1}{\omega} \sin(\omega t) \] Thus, we evaluate: \[ \int_0^{\frac{T}{4}} A \omega \cos(\omega t) \, dt = A \left[ \sin(\omega t) \right]_0^{\frac{T}{4}} = A \left( \sin\left(\frac{\pi}{2}\right) - \sin(0) \right) = A(1 - 0) = A \] 6. **Substitute Back into Mean Velocity**: Now substituting back into the mean velocity formula: \[ v_{mean} = \frac{4}{T} \cdot A = \frac{4A}{T} \] 7. **Final Result**: Therefore, the mean velocity of the particle averaged over a quarter oscillation is: \[ v_{mean} = \frac{4A}{T} \] ### Conclusion: The correct answer is \( \frac{4A}{T} \).

To find the mean velocity of a particle executing Simple Harmonic Motion (SHM) averaged over a quarter of its oscillation, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Motion**: The displacement of a particle in SHM can be described by the equation: \[ x(t) = A \sin(\omega t) ...
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