Home
Class 11
PHYSICS
Natural length of a spring is 60 cm and ...

Natural length of a spring is 60 cm and its spring constant is 4000 N/m. A mass of 20 kg is hung from it. The extension produced in the spring is (Take, `g = 9.8 m//s^(2)`)

A

4.9 cm

B

0.49 cm

C

9.4 cm

D

0.94 cm

Text Solution

AI Generated Solution

The correct Answer is:
To find the extension produced in the spring when a mass is hung from it, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Given Values:** - Natural length of the spring, \( L = 60 \, \text{cm} \) (not directly needed for extension calculation) - Spring constant, \( k = 4000 \, \text{N/m} \) - Mass hung from the spring, \( m = 20 \, \text{kg} \) - Acceleration due to gravity, \( g = 9.8 \, \text{m/s}^2 \) 2. **Calculate the Weight of the Mass:** The weight \( W \) of the mass can be calculated using the formula: \[ W = m \cdot g \] Substituting the values: \[ W = 20 \, \text{kg} \cdot 9.8 \, \text{m/s}^2 = 196 \, \text{N} \] 3. **Apply Hooke's Law:** According to Hooke's Law, the force exerted by the spring is proportional to the extension \( x \): \[ F = k \cdot x \] At equilibrium, the weight of the mass equals the spring force: \[ W = k \cdot x \] Therefore, we can set up the equation: \[ mg = kx \] 4. **Rearranging the Equation to Solve for Extension \( x \):** Rearranging gives us: \[ x = \frac{mg}{k} \] 5. **Substituting the Known Values:** Now substituting the values we calculated: \[ x = \frac{196 \, \text{N}}{4000 \, \text{N/m}} \] 6. **Calculating the Extension:** Performing the division: \[ x = 0.049 \, \text{m} \] 7. **Convert to Centimeters:** To convert meters to centimeters, multiply by 100: \[ x = 0.049 \, \text{m} \times 100 = 4.9 \, \text{cm} \] 8. **Conclusion:** The extension produced in the spring is \( 4.9 \, \text{cm} \). ### Final Answer: The extension produced in the spring is **4.9 cm**.

To find the extension produced in the spring when a mass is hung from it, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Given Values:** - Natural length of the spring, \( L = 60 \, \text{cm} \) (not directly needed for extension calculation) - Spring constant, \( k = 4000 \, \text{N/m} \) - Mass hung from the spring, \( m = 20 \, \text{kg} \) ...
Promotional Banner

Topper's Solved these Questions

  • OSCILLATIONS

    NCERT FINGERTIPS ENGLISH|Exercise Higher Order Thinking Skills|8 Videos
  • OSCILLATIONS

    NCERT FINGERTIPS ENGLISH|Exercise Exemplar Problems|9 Videos
  • MOTION IN A STRAIGHT LINE

    NCERT FINGERTIPS ENGLISH|Exercise NCERT Exemplar|6 Videos
  • PHYSICAL WORLD

    NCERT FINGERTIPS ENGLISH|Exercise Assertion And Reason|10 Videos

Similar Questions

Explore conceptually related problems

A block of mass 20 kg is hung with the help of ideal string, pulleys and spring (Spring constant k = 1000 N/m) as shown in figure. If block is in equilibrium position then extension in the spring will be (g = 10 ms^-2)

A spring has natural length 40 cm and spring constant 500 N//m . A block of mass 1 kg is attached at one end of the spring and other end of the spring is attached to a ceiling. The block is relesed from the position, where the spring has length 45 cm .

A spring has a natural length of 50 cm and a force constant of 2.0 xx 10^(3) N m^(-1) . A body of mass 10 kg is suspended from it and the spring is stretched. If the body is pulled down to a length of 58 cm and released, it executes simple harmonic motion. The net force on the body when it is at its lowermost position of its oscillation is (10x) newton. Find value of x. (Take g=10m/ s^(2) )

A spring has a natural length of 50 cm and a force constant of 2.0 xx 10^(3) N m^(-1) . A body of mass 10 kg is suspended from it and the spring is stretched. If the body is pulled down to a length of 58 cm and released, it executes simple harmonic motion. The net force on the body when it is at its lowermost position of its oscillation is (10x) newton. Find value of x. (Take g=10m/ s^(2) )

A force of 10 N holds an ideal spring with a 20 N/m spring constant in compression. The potential energy stored in the spring is

A mass hangs in equilibrium from a spring of constant K=2N//cm Another mass of 3 kg is placed over M. Find the new amplitude of oscillation after wards (in m) (Take g=10 m// s^(-2))

A block of mass 2kg is attached with a spring of spring constant 4000Nm^-1 and the system is kept on smooth horizontal table. The other end of the spring is attached with a wall. Initially spring is stretched by 5cm from its natural position and the block is at rest. Now suddenly an impulse of 4kg-ms^-1 is given to the block towards the wall. Find the velocity of the block when spring acquires its natural length

A point is located at a distance 100 cm from the screen. A lens of focal length 23 cm mounted on a movable frictionless stand is kept between the object and screen. The stand is attached to massless spring of natural length 50 cm and spring constant 800(N)/(m) as shown in the figure. Mass of the stand with lens is 2 kg. Initially spring is in its natural length. Now a sharp impulse J is given to the stand. Answer the following questions. Q. Choose the correct options (s):

a block of mass 0.1 kg attached to a spring of spring constant 400 N/m pulled horizontally from x=0 to x_1 =10 mm. Find the work done by the spring force

A mass m = 8kg is attached to a spring as shown in figure and held in positioin so that the spring remains unstretched. The spring constant is 200 N/m. The mass m is then released and begins to undergo small oscillations. The maximum velocity of the mass will be (g=10m/ s^(2))

NCERT FINGERTIPS ENGLISH-OSCILLATIONS -Assertion And Reason
  1. Natural length of a spring is 60 cm and its spring constant is 4000 N/...

    Text Solution

    |

  2. Assertion: The motion of the earth around the sun is perriodic but not...

    Text Solution

    |

  3. Assertion: A combination of two simple harmonic motions with a arbitra...

    Text Solution

    |

  4. Assertion: The motion of a simple pendulum is simple harmoni for all a...

    Text Solution

    |

  5. Assertion: Simple harmonic motion is the projection of uniform circula...

    Text Solution

    |

  6. Assertion: The graph of total energy of a particle in SHM with respect...

    Text Solution

    |

  7. Assertion: If the amplitude of a simple harmonic oscillator is doubled...

    Text Solution

    |

  8. Assertion: Every periodic motion is not simple harmonic motion. Reas...

    Text Solution

    |

  9. Assertion: A block of small mass m attached to a stiff spring will hav...

    Text Solution

    |

  10. Assertion: In damped oscillation, the energy of the system is dissipat...

    Text Solution

    |

  11. Assertion: In forced oscillations, th steady state motion of the parti...

    Text Solution

    |

  12. Assertion: An earthquake will not cause uniform damage to all building...

    Text Solution

    |

  13. Assertion: A child in a garden swing periodically presses his feet aga...

    Text Solution

    |

  14. Assertion: The skill in swinging to greater heights lies in the synchr...

    Text Solution

    |

  15. Assertion: In the ideal case of zero damping, the amplitude of simpl h...

    Text Solution

    |

  16. Assertion : The amplitude of oscillation can never be infinite. Reas...

    Text Solution

    |