A particle of mass (m) is attached to a spring (of spring constant k) and has a natural angular frequency `omega_(0)`. An external force `R(t)` proportional to `cos omegat(omega!=omega_0)` is applied to the oscillator. The time displacement of the oscillator will be proportional to.

Options

A. `(m)/(omega_(0)^(2)-omega^(2))`
B. `(1)/(m(omega_(0)^(2)-omega^(2)))`
C. `(1)/(m(omega_(0)^(2)+omega^(2)))`
D. `(m)/(omega_(0)^(2)+omega^(2))`

Answer

B

Explanation

For forced oscillation, the time displacement at any instant is given by
`x=(F_(0))/(m(omega_(0)^(2)-omega^(2)))cosomegat,xprop(1)/(m(omega_(0)^(2)-omega^(2)))`