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A sample of ferrous oxide has actual for...

A sample of ferrous oxide has actual formula `Fe_(0.93)O_(1..00)`. In this sample what fraction of metal ions are `Fe^(2+)` ions? What type of non-stoichiometric defect is present in this sample ?

A

(i)-0.849 , (ii)-Metal deficiency

B

(i)-0.790 , (ii)-Metal deficiency

C

(i)-0.145, (ii)-Metal excess

D

(i)-0.93 , (ii)-Vacancy defect

Text Solution

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The correct Answer is:
To solve the problem, we need to determine the fraction of ferrous ions (Fe²⁺) in the given sample of ferrous oxide, Fe₀.₉₃O₁.₀₀, and identify the type of non-stoichiometric defect present. ### Step-by-Step Solution: 1. **Identify the total number of metal ions**: The formula given is Fe₀.₉₃O₁.₀₀, which indicates that there are 0.93 moles of iron (Fe) per mole of the compound. 2. **Let x be the number of Fe³⁺ ions**: Since some of the Fe²⁺ ions are replaced by Fe³⁺ ions, we can denote the number of Fe³⁺ ions as x. Consequently, the number of Fe²⁺ ions will be (0.93 - x). 3. **Set up the charge balance equation**: The total positive charge contributed by the metal ions must equal the total negative charge from the oxide ions. The charge from the oxide ions (O²⁻) is -2 for each O, and since there is 1 mole of O, the total negative charge is -2. The total positive charge from the metal ions can be expressed as: \[ 3x + 2(0.93 - x) = 2 \] Here, 3x is the contribution from Fe³⁺ ions and 2(0.93 - x) is the contribution from Fe²⁺ ions. 4. **Simplify the equation**: \[ 3x + 1.86 - 2x = 2 \] \[ x + 1.86 = 2 \] \[ x = 2 - 1.86 = 0.14 \] 5. **Calculate the number of Fe²⁺ ions**: The number of Fe²⁺ ions is: \[ 0.93 - x = 0.93 - 0.14 = 0.79 \] 6. **Calculate the fraction of Fe²⁺ ions**: The fraction of Fe²⁺ ions in the sample is given by: \[ \text{Fraction of Fe}^{2+} = \frac{\text{Number of Fe}^{2+}}{\text{Total number of metal ions}} = \frac{0.79}{0.93} \] \[ \text{Fraction of Fe}^{2+} \approx 0.849 \] 7. **Identify the type of non-stoichiometric defect**: Since the formula shows a deficiency of iron (Fe) ions (from Fe₁ to Fe₀.₉₃), this indicates a metal deficiency defect. ### Final Answers: - The fraction of Fe²⁺ ions is approximately **0.849**. - The type of non-stoichiometric defect present is **metal deficiency**.

To solve the problem, we need to determine the fraction of ferrous ions (Fe²⁺) in the given sample of ferrous oxide, Fe₀.₉₃O₁.₀₀, and identify the type of non-stoichiometric defect present. ### Step-by-Step Solution: 1. **Identify the total number of metal ions**: The formula given is Fe₀.₉₃O₁.₀₀, which indicates that there are 0.93 moles of iron (Fe) per mole of the compound. 2. **Let x be the number of Fe³⁺ ions**: ...
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