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in which of the following structures c...

in which of the following structures coordination number for cations and anions in the packed structure will be same ?

A

`Cl^-` ions form fcc lattice and `Na^+` ions occupy all octahedral voids of the unit cell.

B

`Ca^(2+)` ions form fcc lattice and `F^-` ions occupy all the eight tetrahedral voids of the unit cell

C

`O^(2-)` ions form fcc lattice and `Na^(+)` ions occupy all the eight tetrahedral voids of the unit cell

D

`S^(2-)` ions form fcc lattice and `Zn^(2+)` ions go into alternate tetrahedral voids of the unit cell

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The correct Answer is:
To solve the question, we need to analyze the coordination numbers of cations and anions in different crystal structures. The coordination number refers to the number of nearest neighbors surrounding a particular ion in a crystal lattice. ### Step-by-Step Solution: 1. **Understanding Coordination Number**: - The coordination number is defined as the number of ions of opposite charge that surround a given ion in a crystal lattice. For example, in NaCl, each Na+ ion is surrounded by six Cl- ions. 2. **Analyzing NaCl Structure**: - In NaCl, the chloride ions (Cl-) form a face-centered cubic (FCC) lattice. The sodium ions (Na+) occupy the octahedral voids in this lattice. - Each Na+ ion is surrounded by six Cl- ions, and each Cl- ion is also surrounded by six Na+ ions. - Therefore, the coordination number for both Na+ and Cl- in NaCl is 6. 3. **Examining Other Structures**: - **Option B (CaF2)**: In calcium fluoride (CaF2), Ca2+ ions form an FCC lattice, while F- ions occupy the tetrahedral voids. Here, the coordination number for Ca2+ is 8, and for F-, it is 4. Thus, they are not equal. - **Option C (Na2O)**: In sodium oxide (Na2O), O2- ions form an FCC lattice, and Na+ ions occupy the tetrahedral voids. The coordination number for O2- is 4, while for Na+, it is 8. Again, they are not equal. - **Option D (SnO)**: In tin(II) oxide (SnO), Sn2+ ions occupy octahedral voids, while O2- ions form an FCC lattice. The coordination number for Sn2+ is 6, while for O2- is 4. They are not equal. 4. **Conclusion**: - From the analysis, only in NaCl do the cations and anions have the same coordination number, which is 6. Therefore, the correct answer is **Option A (NaCl)**. ### Final Answer: The correct structure where the coordination number for cations and anions is the same is **NaCl**. ---

To solve the question, we need to analyze the coordination numbers of cations and anions in different crystal structures. The coordination number refers to the number of nearest neighbors surrounding a particular ion in a crystal lattice. ### Step-by-Step Solution: 1. **Understanding Coordination Number**: - The coordination number is defined as the number of ions of opposite charge that surround a given ion in a crystal lattice. For example, in NaCl, each Na+ ion is surrounded by six Cl- ions. 2. **Analyzing NaCl Structure**: ...
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NCERT FINGERTIPS ENGLISH-THE SOLID STATE -EXEMPLAR PROBLEMS
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