Calculate the cell potential for Cu plate kept in 0.2 M `CuSO_(4)` solution. `[E_(Cu^(+)|Cu^(2+))^(Theta)=0.34V]`

Explanation

According to Nernst equation the potential of this electrode,
`E_(Cu^(2+)|Cu)=E_(Cu^(2+)|Cu)^(Theta)-(0.059)/(n)"log"(1)/([Cu^(2+)])`
`=0.34V-0.0295("log"(1)/(0.2))`
`=0.34V-(0.0295)(log5.0)`
`=0.34-(0.0295)(0.6990)`
`=0.34-0.0206`
`=0.3194V`