What is the Nernst formula of calculate reduction potential of non standard electrode of `Zn|Zn^(2+) `?

Options

A. `E_(Zn^(2+)|Zn)=E_(Zn^(2+)|Zn)^(Theta)-(0.059)/(2)log[Zn^(2+)]`
B. `E_(Zn^(2+)|Zn)=E_(Zn^(2+)|Zn)^(Theta)-(0.059)/(2)log[(1)/(Zn^(2+))]`
C. `E_(Zn^(2+)|Zn)=E_(Zn^(2+)|Zn)^(Theta)+(0.059)/(n)log[Zn^(2+)]`
D. `E_(Zn^(2+)|Zn)=E_(Zn^(2+)|Zn)^(Theta)+(0.059)/(2)log[Zn^(2+)]`

Answer

A

Explanation

e.g., `Zn+Cu^(2+) to Zn^(2+)+Cu_((S)) and Zn|Zn^(2+)` is oxidation.
In which Zn is reactant and `Zn^(2+)` is a product. And n=2.
`therefore kappa (["Product"])/(["Reactant"])=([Zn^(2+)])/(Zn)=[Zn^(2+)]`
`E_(Zn^(2+)|Zn)=E_(Zn^(2+)|Zn)^(Theta)-(0.059)/(2)log[Zn^(2+)]`