What is the correct Nernst formula of calculate potential of reaction `Zn_((aq))^(2+)+2e^(-) to Zn_((S))`

Options

A. `E_(Zn^(2+)|Zn)=E_(Zn^(2+)|Zn)^(Theta)-(0.059)/(2)log[Zn_((aq))^(2+)]`
B. `E_(Zn^(2+)|Zn)=E_(Zn^(2+)|Zn)^(Theta)-(0.059)/(2)log"(1)/([Zn_((aq))^(2+)])`
C. `E_(Zn^(2+)|Zn)=E_(Zn^(2+)|Zn)^(Theta)+(0.059)/(2)log[Zn_((aq))^(2+)]`
D. `E_(Zn^(2+)|Zn)=E_(Zu^(2+)|Zn)^(Theta)+(0.059)/(2)"log"(1)/([Zn_((aq))^(2+)])`

Answer

A, B, C, D

Explanation

`Zn_((aq))^(2+)+2e^(-) to Zn_((S))`
Where, Reactants=`[Zn_((aq))^(2+)],` Product=[Zn]
`therefore "log "K_(c)=(["Product"])/(["Reactant"])=([Zn_((S))])/([Zn_((aq))^(2+)])=(1)/([Zn^(2+)])`
`therefore E_(Zn^(2+)|Zn)=E_(Zn^(2+)|Zn)^(Theta)-(0.059)/(2)"log"(1)/([Zn_((aq))^(2+)])`
Or `E_(Zn^(2+)|Zn)=E_(Zn^(2+)|Zn)^(Theta)+(0.059)/(2)log[Zn^(2+)]`