When redox reaction stops by achieving equilibrium then what will be true for `E_(cell)^(Theta)` of following reaction ?
`Al_((S)) +3Cu_((aq))^(2+) to 2Al_((aq))^(3+)+3Cu_((S))`

Options

A. `E_(cell)^(Theta)=(0.059)/(2)"log"([Al^(3+)]^(2))/([Cu^(2+)]^(2))`
B. `E_(cell)^(Theta)=(0.059)/(6)"log"([Al^(3+)])/([Cu^(2+)])`
C. `E_(cell)^(Theta)=(0.059)/(6)"log"([Al^(3+)]^(2))/([Cu^(2+)]^(3))`
D. `E_(cell)^(Theta)=0.059"log"([Al^(3+)]^(2))/([Cu^(2+)]^(3+))`

Answer

C

Explanation

`E_(cell)^(Theta)=(0.059)/(6)"log"([Al^(3+)]^(2))/([Cu^(2+)]^(3))`