If `E_(cell)^(@)` of electrochemical cell=1.1 V for possessing following chemical reaction, then what is `E_(cell)` ?
`Zn_((S))+Cu_((aq))^(2+)(0.1M) to Zn^(2+)(1M)+Cu_((S))`

Options

A. 2.12 V
B. 1.8 V
C. 1.07 V
D. 0.84 V

Answer

C

Explanation

According to following reaction, `n=2`.
`E_(cell)=E_(cell)^(@)-(0.0592)/(n)"log"([Zn^(2+)])/([Cu^(2+)])`
`=1.1-(0.0592)/(2)"log"((1.0)/(0.1))`
`=1.1-0.0296log10`
`=1.1-0.296=1.0704V~~1.07V`