`E^(@)` value of following half-cell in standard conditions are given as follows :
`[E_(Fe^(3+)|Fe^(2+))^(o)=0.77V,E_(Sn^(2+)|Sn)^(o)=-0.14V]` by using such value calculate potential of given reaction ?
`Sn_((S))+2Fe_((aq))^(3+) to 2Fe_((aq))^(2+)+Sn_((aq))^(2+)`.

Options

A. 0.91V
B. 1.40V
C. 1.68V
D. 0.63V

Answer

A

Explanation

`E^(o)=E_(Fe^(2+)|Fe^(2))^(o)-E_(Sn^(2+)|Sn)^(o)`
`=0.77-(-0.14)=0.91V`.