If pH of hydrogen electrode is 10, then what is the potential of it . . .

Options

A. 0.59 V
B. 0.00 V
C. `-0.59V`
D. `-0.059V`

Answer

C

Explanation

`H_((aq))^(+)+e^(-) to (1)/(2)H_((g))` (reduction)
`E=E^(@)-(0.059)/(n)"log"(1)/([H^(+)])`
`=0.0-(0.059)/(1)pH`
`=0-0.059xx10`
`=-0.59V`