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Standard reduction potential of Zn^(2+)/...

Standard reduction potential of `Zn^(2+)//Zn,Ni^(2+)//Ni` and `Fe^(2+)//Fe` are -0.76 V, -0.23 V and -0.44 V respectively. So in which condition reaction `X+Y^(2+) to Y+X^(2+)` would be spontaneous ?

A

`X=Ni,Y=Fe`

B

`X=Ni,Y=Zn`

C

`X=Fe,Y=Zn`

D

`X=Zn,Y=Ni`

Text Solution

Verified by Experts

The correct Answer is:
D

`Zn_((S))+Ni_((aq))^(2+) to Zn_(Ni^(2+)//Ni)^(@)-E_(Zn^(2+)//Zn)^(@)`
`=-0.23-(-0.76)=+0.52V`.
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