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5600 ml of O(2) is obtained by electroly...

5600 ml of `O_(2)` is obtained by electrolysis at STP, then how much Ag is obtained by same electricity ? (atomic mass of Ag=108)

A

`5.4gm`

B

`10.8gm`

C

`54.0gm`

D

`108.0gm`

Text Solution

Verified by Experts

The correct Answer is:
D
`n_(O_(2))=(5600)/(22400)=(1)/(4)` mol `O_(2)`
`(W_(Ag))/(108)xx1=(W_(O_(2)))/(M_(O_(2)))xx4" "(2H_(2)O to O_(2)+4H^(+)+4e^(-))`
`(W_(Ag))/(108)xx1=(W_(O_(2)))/(M_(O_(2)))xx4`
`(W_(Ag))/(108)=(1)/(4)xx4" "therefore W_(Ag)=108gm`.
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