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Number of electrons liberated on cathode...

Number of electrons liberated on cathode by passing 1 ampere current for 60 second during electrolysis is . . . .(Charge on electrone `=1.60xx10^(-19)C`)

A

`3.75xx10^(20)`

B

`7.48xx10^(23)`

C

`6xx10^(23)`

D

`6xx10^(20)`

Text Solution

Verified by Experts

The correct Answer is:
A
`Q=n*e^(-)`
`Ixxt=n*e^(-)`
`n=(1xx60)/(1.6xx10^(-19))=3.75xx10^(20)e^(-)`
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