At 298 K temperature, how much pressure of `H_(2)` is required to make hydrogen electrode potential of pure water be zero ?

Options

A. `10^(-12)` atm
B. `10^(-10)` atm
C. `10^(-4)` atm
D. `10^(-14)` atm

Answer

D

Explanation

`E=E^(@)-(0.0591)/(2)"log"(p_(H_(2)))/([H^(+)]^(2))`
`=0-(0.0591)/(2)"log"(p_(H_(2)))/((10^(-7))^(2))`
So, if `p_(H_(2))=10^(-14)` then potential of hyddrogen electrode will be 0.