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Given that the standard potential , E^(@...

Given that the standard potential , `E^(@)` of `Cu^(2+)|Cu` and `Cu^(+)|Cu` are 0.340 V and 0.522 V respectively. The `E^(@)` of `Cu^(2+)|Cu^(+)` is:

A

0.158 V

B

`-0.158 V`

C

`0.182V`

D

`-0.182V`

Text Solution

Verified by Experts

The correct Answer is:
A

`Cu^(2+)+2e^(-) to Cu" "E^(@)=0.340V `
`underline(Cu to Cu^(+) +e^(-))" "E^(@)=-0.522V`
`Cu^(2+)+e^(-) to Cu^(+)" "E^(@)=(?)`
Applying, `DeltaG=nFE^(@)`
`(-1xxFxxE^(@))=(-2xxFxx0.340)`
`=(-2xxFxx0.340)-(-1xxFxx-0.522)`
`=-2xxFxx0.340+1xxFxx0.522`
`-1xxFxxE^(@)=-1Fxx0.158V`
`therefore E^(@)=0.158V`
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