4.5 g of a compound (M.W. = 90) is required to form an aqueous solution of volume 250ml. The molarity of solution is:

4.5 g of compound.A (MW=90) was used to make 250 mL of its aqueous solution. The molarity of the solution in Mis "x"xx10^(-1) . The value of x is (Rounded off to the nearest integer)

The volume of water is required to make 0.20 M solution from 1 mL of 0.5 M solution is :

4.5g mass of a substance (molar mass = 90g/mol) is dissolved in 250ml solution, the molarity of solution is

Molarity of 1m aqueous NaOH solution [density of the solution is 1.02 g/ml]

18g of glucose (molar mass 180g "mol"^(-1) ) is present in 500CM^(3) of its aqueous solution. What is the molarity of the solution? What additional data is required if the molality of the solution is also required to be calculated?

A 30% (W/W) aqueous solution has density 2gm/ml and molarity 2M, then molar mass of solute is:

The molarity of a solution containing 5.0 g of NaOH in 200 mL solution is