Find the total number of amphoteric compound from following `BeO,Be(OH)_2,BaO,Sr(OH)2`

Answer

To determine the total number of amphoteric compounds among the given substances (BeO, Be(OH)₂, BaO, Sr(OH)₂), we need to analyze each compound based on the definition of amphoteric compounds.

### Step-by-Step Solution:

1. **Understanding Amphoteric Compounds**:
Amphoteric compounds are those that can act as both acids and bases. This means they can react with both acids and bases.

2. **Analyzing Each Compound**:
- **BeO (Beryllium Oxide)**:
- Beryllium oxide is known to exhibit amphoteric behavior. It can react with acids to form beryllium salts and with bases to form beryllates.
- **Reactions**:
- With acid: BeO + 2HCl → BeCl₂ + H₂O
- With base: BeO + 2NaOH + 2H₂O → Na₂Be(OH)₄
- Conclusion: BeO is amphoteric.

- **Be(OH)₂ (Beryllium Hydroxide)**:
- Beryllium hydroxide is also amphoteric. It reacts with acids to form beryllium salts and with strong bases to form beryllates.
- **Reactions**:
- With acid: Be(OH)₂ + 2HCl → BeCl₂ + 2H₂O
- With base: Be(OH)₂ + 2NaOH → Na₂Be(OH)₄
- Conclusion: Be(OH)₂ is amphoteric.

- **BaO (Barium Oxide)**:
- Barium oxide is a basic oxide. It does not exhibit amphoteric behavior as it reacts only with acids.
- **Reactions**:
- With acid: BaO + 2HCl → BaCl₂ + H₂O
- Conclusion: BaO is not amphoteric.

- **Sr(OH)₂ (Strontium Hydroxide)**:
- Strontium hydroxide is a strong base and does not exhibit amphoteric behavior. It reacts only with acids.
- **Reactions**:
- With acid: Sr(OH)₂ + 2HCl → SrCl₂ + 2H₂O
- Conclusion: Sr(OH)₂ is not amphoteric.

3. **Counting the Amphoteric Compounds**:
- From the analysis above, we found that:
- BeO is amphoteric.
- Be(OH)₂ is amphoteric.
- BaO is not amphoteric.
- Sr(OH)₂ is not amphoteric.
- Therefore, the total number of amphoteric compounds is **2** (BeO and Be(OH)₂).

### Final Answer:
The total number of amphoteric compounds from the given list is **2**.