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ABC is a triangle and 'O', any point in the palne of the triangle. The lines AO, BO and CO meet the sides BC, CA and AB is D,E,F respectively. Then `(OD)/(AD)+(OE)/(BE)+(OF)/(CF)` equal to

A

1

B

`-1`

C

`(OD)/(AD).(OE)/(BE).(OF)/(CF)`

D

0

Text Solution

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The correct Answer is:
A
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