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Cos^(-1)("cos"(5pi)/4)=...

`Cos^(-1)("cos"(5pi)/4)=`

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The correct Answer is:
`(3pi)/4`
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AAKASH SERIES-INVERSE TRIGONOMETRIC FUNCTIONS-EXERCISE 7.1 (VERY SHORT ANSWER QUESTIONS)
  1. Find the values of the following: sin((pi)/2-Sin^(-1)((-sqrt(3))/2))

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  2. Find the values of the following: Sin^(-1)("sin"(5pi)/6)

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  3. Cos^(-1)("cos"(5pi)/4)=

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  4. Find the values of the following: Tan^(-1)("tan"(3pi)/4)

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  5. Find the values of the following: Sin^(-1)("sin"(33pi)/7)

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  6. Find the values of the following: Cos^(-1)("cos"(17pi)/6)

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  7. Find the values of the following: Cos^(-1)("cos"(2pi)/3)

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  8. Find the values of the following: cos("Sin"^(-1)4/5)

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  9. Find the values of the following: tan("Sec"^(-1)25/7)

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  10. Find the values of the following: sin("cos"^(-1)5/13)

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  11. Find the values of the following: tan("Cosec"^(-1)13/12)

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  12. Find the values of the following: cos("Tan"^(-1)5/12)

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  13. Find the values of the following: sin^(2)("Cot"^(-1)4/3)

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  14. Find the values of the following: sin((pi)/2-Sin^(-1)(-4/5))

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  15. Find the value of the following: sin(2"Sin"^(-1)4/5)

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  16. Find the value of the following: tan[1/2cos^(-1)(1/3)]

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  17. Find the value of the following: cos(Cos^(-1)(-2/3)-Sin^(-1)(2/3))

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  18. Simplify each of the following: tan^(-1)((Sinx)/(1+Cosx))

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  19. Simplify each of the following: tan^(-1)(Secx+tanx)

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  20. Write the following function in the simplest form : tan^(-1)(sqrt((1...

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