Home
Class 11
MATHS
Sin^(-1)("sin"(2pi)/3)=...

`Sin^(-1)("sin"(2pi)/3)=`

A

`(2pi)/3`

B

`(pi)/3`

C

`-(pi)/3`

D

`-(2pi)/3`

Text Solution

Verified by Experts

The correct Answer is:
B
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • INVERSE TRIGONOMETRIC FUNCTIONS

    AAKASH SERIES|Exercise EXERCISE-II|71 Videos

  • INVERSE TRIGONOMETRIC FUNCTIONS

    AAKASH SERIES|Exercise PRACTICE EXERCISE|37 Videos

  • INVERSE TRIGONOMETRIC FUNCTIONS

    AAKASH SERIES|Exercise ADDITIONAL EXERCISE|7 Videos

  • INVERSE TRIGNOMETRIC FUNCTIONS

    AAKASH SERIES|Exercise ADDITIONAL PRACTICE EXERCISE (LEVEL - II PRACTICE SHEET (ADVANCED) INTEGER TYPE QUESTIONS)|7 Videos

  • INVERSET TRIGONOMETRIC FUNCTIONS

    AAKASH SERIES|Exercise ADDITIONAL PRACTICE EXERCISE (LEVEL-II PRACTICE SHEET (ADVANCED) INTEGER TYPE QUESTIOS)|5 Videos

Similar Questions

Explore conceptually related problems

Find the values of the following: sin^(-1)("sin"(4pi)/3)

Find the values of sin^(-1)("sin"(3pi)/5)

Knowledge Check

  • The value of the expression Sin^(-1)(Sin""(22pi)/7)+Cos^(-1)(Cos""(5pi)/3)+Tan^(-1)(Tan""(5pi)/7)+Sin^(-1)(Cos2) is

    A
    `(17pi)/42-2`
    B
    -2
    C
    `-pi/21-2`
    D
    `pi/21`

  • If sin^(-1)(x)+sin^(-1)(2x)=(pi)/3 then x=

    A
    `3/28`
    B
    `(sqrt(3))/28`
    C
    `sqrt(3/28)`
    D
    `3/(sqrt(28))`

  • If Sin^(-1)x+Sin^(-1)y=2pi//3,"then "Cos^(-1)x+Cos^(-1)y=

    A
    `2pi//3`
    B
    `pi//3`
    C
    `pi//6`
    D
    `pi`

    • Similar Questions

    Explore conceptually related problems

    Find the values of the following. (i) sin^(-1) (sin "" (4pi)/(3) )

    solve the following equations sin^(-1)x+sin^(-1)2x=(pi)/3

    The number of solutions of the equation sin^(-1)x+sin^(-1)2x=pi/3 is

    The positive integer value of n gt 3 satisfying the equation (1)/( sin ((pi )/(n)) ) = (1)/( sin ((2pi)/(n ))) + (1)/( sin ((3pi)/( n ))) is

    sin ""(pi)/(14).sin""(3pi)/(14).sin""(5pi)/(14).sin""(7pi)/(14).sin""(9pi)/(14).sin""(11pi)/(14).sin""(13pi)/(14)=

    Home
    Profile