sec^(2)(Tan^(-1)2)+cosec^(2)(Cot^(-1)3)=...

`sec^(2)(Tan^(-1)2)+cosec^(2)(Cot^(-1)3)=`

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cos^(-1)("cos"(7pi)/6) is equal to
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sin^(-1)((sqrt(3))/2)-tan^(-1)(-sqrt(3))=
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sec^(2)(Tan^(-1)2)+cosec^(2)(Cot^(-1)3)=
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cos[sin^(-1)(-4//5)-cos^(-1)(4//5)]=
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sec^(-1)((2sqrt(2))/(1+sqrt(3)))=
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I. sin("Cos"^(-1)3/5)=4/5 II. cos("Tan"^(-1)7/24)=24/25
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cos(sin^(-1)63//65)=
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cos^(-1)(8/17)-cos^(-1)(5/13)=
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Sin^(-1)(4/5)-Sin^(-1)(5/13)=
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tan^(-1)(2+)tan^(-1)(3)=
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2tan^(-1)(1//2)+sin^(-1)(3//5)=
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The value of tan^(-1)(m/n)-tan^(-1)((m-n)/(m+n)) is
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2"tan"^(-1)1/5+"tan"^(-1)1/7+2"tan"^(-1)1/8=
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cos[2"tan"^(-1)1/5+"cos"^(-1)63/65]=
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tan(1/2Cos^(-1)0)=
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sin(2tan^(-1)(8/15))=
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cos(2cos^(-1)(7//25))=
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If tan^(-1)x+tan^(-1)y+tan^(-1)z=pi then x+y+z=
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If cos^(-1) x + cos^(-1) y + cos^(-1) z = 3pi , then
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If sin^(-1)(a//x)+sin^(-1)(b//x)=pi//2 then x=
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