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tan^(-1)[(cosx)/(1+sinx)] is equal to...

`tan^(-1)[(cosx)/(1+sinx)]` is equal to

A

`(pi)/4-x/2,` for `x in ((-pi)/2,(3pi)/2)`

B

`(pi)/4-x/2`, for `x in ((-pi)/2,(pi)/2)`

C

`(pi)/4-x/2` for `x in ((3pi)/2,(5pi)/2)`

D

`(pi)/4-x/2`, for `x in ((-3pi)/2,(-pi)/2)`

Text Solution

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The correct Answer is:
A
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