For a given data `: E_(Mg^(2+) // Mg)^(@) = -2.37 V , E_(Cu^(2+)// Cu)^(@) = + 0.34 V `
Calculate the emf of the cell in which the following reaction takes place .
` underset((0.0001 M)) ( Mg_((s))) + Cu_((aq))^(2+) underset((0.001M)) to Mg_((aq))^(2+) + Cu_((s))`

Explanation

`E_("cell")^(@) = E_(Cu^(2+)//Cu)^(@) -E_(Mg^(2+)//Mg)^(@) `
`= 0.34 - (-2.37) = 2.71V`
` E_("cell") = E_("cell")^(@) - (0.0591)/(n) log""([Mg^(2+)])/([Cu^(2+)]) ` at 298 K
` E_("cell") = 2.71 - (0.0591)/(2) log ""(0.001)/(0.0001)=2.68 V `