If linear momentum if increased by `50%` then kinetic energy will be increased by

Options

A. 0.5
B. 1
C. 1.25
D. 0.25

Answer

C

Explanation

Let `P_(1)=P, P_(2)=P_(1)+50%` of `P_(1)=P_(1)+(P_(1))/(2)=(3P_(1))/(2)`
`E prop P^(2)rArr (E_(2))/(E_(1))=((P_(2))/(P_(1)))^(2)=((3P_(1)//2)/(P_(1)))^(2)=(9)/(4)`
`rArr E_(2)=2.25E = E_(1)+1.25 E_(1)`
`therefore E_(2)=E_(1)+125%` of `E_(1)`
i.e. kinetic energy will increase by 125%.