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Two bodies A and B having masses in the ratio of 3 : 1 possess the same kinetic energy. The ratio of their linear momenta is then

A

`3:1`

B

`9:1`

C

`1:1`

D

`sqrt3:1`

Text Solution

Verified by Experts

The correct Answer is:
D
`P=sqrt(2mE)therefore (P_(1))/(P_(2))=sqrt((m_(1))/(m_(2))` (if E = constant)
`therefore (P_(1))/(P_(2))=sqrt((3)/(1))`
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