If a lighter body (mass `M_(1)` and velocity `V_(1)` ) and a heavier body (mass `M_(2)` and velocity `V_(2)`) have the same kinetic energy, then-

Options

A. `M_(2)V_(2)ltM_(1)V_(1)`
B. `M_(2)V_(2)=M_(1)V_(1)`
C. `M_(2)V_(1)=M_(1)V_(2)`
D. `M_(2)V_(2)gtM_(1)V_(1)`

Answer

D

Explanation

`P=sqrt(mE)`. If kinetic energy are equal then `P prop sqrt(m)`
i.e., heavier body posses large momentum
As `M_(1)lt M_(2)` therefore, `M_(1)V_(1)lt M_(2)V_(2)`