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If a body of mass 200 g falls a height 2...

If a body of mass 200 g falls a height 200 m and its total P.E. is converted into K.E. at the point of contact of the body with earth surface. Then what is the decrease in P.E. of the body at the contact.
`(g=10m//s^(2))`

A

200 J

B

400 J

C

600 J

D

900 J

Text Solution

Verified by Experts

The correct Answer is:
B
`Delta U = mgh = 0.2xx10xx200=400 J`
`therefore` Gain in K.E. = decrease in P.E. = 400 J.
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