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If the momentum of a body is increased b...

If the momentum of a body is increased by 100%, then the percentage increase in the kinetic energy is

A

1.5

B

2

C

2.25

D

3

Text Solution

Verified by Experts

The correct Answer is:
D
`E=(P^(2))/(2m)rArr E_(2)=E_(1)((P_(2))/(P_(1)))^(2)=E_(1)((2P)/(P))^(2)`
`rArr E_(2)=4E=E+3E=E+300 %` of E.
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