A block of mass `m` at rest is acted upon by a force `F` for a time t. The kinetic energy of block after time t is

Options

A. `(F^(2)t^(2))/(m)`
B. `(F^(2)t^(2))/(2m)`
C. `(F^(2)t^(2))/(3m)`
D. `(Ft)/(2m)`

Answer

B

Explanation

Kinetic energy `E=(P^(2))/(2m)=((Ft)^(2))/(2m)=(F^(2)t^(2))/(2m) " "` [As P = F t]