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A stationary partical explodes into two ...

A stationary partical explodes into two partical of a masses `m_(1) and m_(2)` which move in opposite direction with velocities `v_(1) and v_(2)`. The ratio of their kinetic energies `E_(1)//E_(2)` is

A

`m_(1)//m_(2)`

B

1

C

`m_(1)v_(2)//m_(2)v_(1)`

D

`m_(2)//m_(1)`

Text Solution

Verified by Experts

The correct Answer is:
D

`E=(P^(2))/(2m)rArr E prop (1)/(m)rArr (E_(1))/(E_(2))=(m_(2))/(m_(1))`
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