A particle of mass m1 is moving with a velocity `v_(1)` and another particle of mass `m_(2)` is moving with a velocity v2. Both of them have the same momentum but their different kinetic energies are E1 and E2 respectively. If `m_(1) gt m_(2)` then

Options

A. `E_(1)ltE_(2)`
B. `(E_(1))/(E_(2))=(m_(1))/(m_(2))`
C. `E_(1)gtE_(2)`
D. `E_(1)=E_(2)`

Answer

A

Explanation

`E=(P^(2))/(2m)` if P = constant then `E prop (1)/(m)`
According to problem `m_(1)gt m_(2) therefore E_(1)lt E_(2)`