A block of mass m initially at rest is dropped from a height h on to a spring of force constant k . the maximum compression in the spring is x then

Options

A. `mgh=(1)/(2)kx^(2)`
B. `mg(h+x)=(1)/(2)kx^(2)`
C. `mgh=(1)/(2)k(x+h)^(2)`
D. `mg(h+x)=(1)/(2)k(x+h)^(2)`

Answer

B

Explanation

Change in gravitational potential energy = Elastic potential energy stored in compressed spring
`rArr mg(h + x)=(1)/(2)kx^(2)`