A body of mass 2 kg collides with a wall with speed 100 m / s and rebounds with same speed. If the time of contact was 1/50 second, the force exerted on the wall is

Options

A. 8N
B. `2xx10^(4)N`
C. 4N
D. `10^(4)N`

Answer

B

Explanation

`F= (dp)/(dt)= m (dv)/(dt)= (m xx 2v)/(1//50) = (2 xx 2 xx 100)/(1//50)= 2 xx 10^(4)N`