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Two masses m(A) and m(B) moving with vel...

Two masses `m_(A)` and `m_(B)` moving with velocities `v_(A)` and `v_(B)` in opposite direction collide elastically after that the masses `m_(A)` and `m_(B)` move with velocity `v_(B)` and `v_(A)` respectively. The ratio `(m_(A)//m_(B))` is

A

1

B

`(v_(A)-v_(B))/(v_(A)+v_(B))`

C

`(m_(A)+m_(B))//m_(A)`

D

`v_(A)//v_(B)`

Text Solution

Verified by Experts

The correct Answer is:
A

Since bodies exchange their velocities, hence their masses are equal so that `(m_(A))/(m_(B))=1`
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