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A body of mass m moving with velocity v makes a head-on collision with another body of mass 2 m which is initially at rest. The loss of kinetic energy of the colliding body (mass m ) is

A

`(1)/(2)` of its initial kinetic energy

B

`(1)/(9)` of its initial kinetic energy

C

`(8)/(9)` of its initial kinetic energy

D

`(1)/(4)` of its initial kinetic energy

Text Solution

Verified by Experts

The correct Answer is:
C

`(Delta K)/(K)= [1- ((m_(1)-m_(2))/(m_(1) + m_(2)))^(2)] = [1- ((m-2m)/(m+2m))^(2)] = (8)/(9)`
`Delta K= (8)/(9)K` i.e. loss of kinetic energy of the colliding body is `(8)/(9)` of its initial kinetic energy
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