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3(sin x + cos x )^(4) + 6(sin x - cos x ...

`3(sin x + cos x )^(4) + 6(sin x - cos x )^(2) + 4(sin^(6) x + cos^(6) x )=`

A

10

B

11

C

12

D

13

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The correct Answer is:
D
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3(sinx-cosx)^(4)+6(sinx+cosx)^(2) + 4(sin^(6) x+cos^(6)x) is equal to

2(sin^(6) x + cos^(6) x ) -3(sin^(4) x + cos^(4) x ) +1=

If y= ( sin^(4) x - cos^(4) x + sin^(2) x cos^(2) x )/( sin^(4) x + cos^(4) x + sin^(2) x cos^(2) x) , x in ( 0, (pi)/(2) ) , then

int_(0)^(2pi) x sin^(4) x cos^(6) x dx=

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5 sin x + 4 cos x =3 rArr 4 sin x - 5 cos x=

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sin 3 x + 2 csin 4x + sin 6x = 4 cos ^(2) x sin 4x

AAKASH SERIES-TRIGONOMERTIC RATIOS-PRACTICE EXERCISE
  1. If cot theta=-3//4 and theta is not in the second quadrant , then ...

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  2. If tan 20^(@) = lambda , " then " (tan 250^@ + tan 340^(@))/(tan 200^...

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  3. 3(sin x + cos x )^(4) + 6(sin x - cos x )^(2) + 4(sin^(6) x + cos^(6) ...

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  4. If k=( sec A + tan A) ( sec B+ tan B) sec C + tan C)=(sec A - tan A)(s...

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  5. In Delta le ABC, 3 tan A+4=0 then the quadratic equation whose roots a...

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  6. If sin theta , cos theta are ther roots of the equation ax^(2)-bx+c...

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  7. If (x)/(a) cos theta + (y)/(b) sin theta = 1 , (x)/(a) sin theta - (y...

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  8. If x = h + p Sec alpha, y = k + q cosec alpha then ((p)/(x-h))^(2) +((...

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  9. If x=a("cosec" theta + cot theta ) , y=b( " cosec " theta - cot theta ...

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  10. (1+cosec theta - cot theta)/(1+cosec theta + cot theta)=

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  11. (1)/(sec^(4) alpha ) +(1)/("cosec"^(4) alpha ) +(2)/(sec^(2) alpha + ...

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  12. ( cos^(3) A + sin^(3) A )/( cos A + sin A ) + (cos^(3) A - sin^(3)A)/(...

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  13. If cosec theta + cot theta = 1//3 then cosec theta - cot theta =

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  14. If cosec A = 4x + (1)/(16x) then cosec A + cot A =

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  15. If tan theta = 5 a - (1)/(20a) then sec theta + tan theta =

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  16. If 1+4 tan theta = 4 sec theta then cos theta=

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  17. 1-(sin^(2) theta)/(1+cos theta) + (1+cos theta)/(sin theta) - (sin the...

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  18. If sin theta, cos theta, tan theta are in GP then cos^(9)theta + cos^(...

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  19. (1+ tan alpha tan beta)^(2) + (tan beta - tan beta)^(2)=

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  20. If 2 Cos^(2)B - 1 = Tan^(2) A then Cos A Cos B =

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