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If a sin^(2) theta+bcos^(2) theta = c, t...

If `a sin^(2) theta+bcos^(2) theta = c`, then `tan^(2) theta` =

A

`(b-c)/(a-c)`

B

`(c-b)/(a-c)`

C

`(a-c)/(b-c)`

D

`(a-c)/(c-b)`

Text Solution

Verified by Experts

The correct Answer is:
B
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