Given below are two statements
Statement 1: Colourless cuprie metaborate is reduced to cuprous metaborate in a luminous flame.
Statement II : Cuprous metaborate is obtained by heating boric anhydride and copper sulphate in a non-luminous flame.
In the light of the above statements, choose the most appropriate answer from the options given below

Options

A. Statement I is true but Statement II is false
B. Both Statement I and Statement II are false
C. Statement I is false but Statement. Il is true
D. Both Statement I and Statement II are true

Answer

To solve the problem, we need to analyze the two statements provided regarding cupric and cuprous metaborate.

### Step-by-Step Solution:

1. **Understanding Statement 1**:
- The statement claims that "Colourless cupric metaborate is reduced to cuprous metaborate in a luminous flame."
- Cupric metaborate is typically blue in color, not colorless. The reduction process involves converting cupric (Cu^2+) to cuprous (Cu^+), which indeed occurs in a luminous flame, but the initial compound is incorrectly described as colorless.

2. **Conclusion for Statement 1**:
- Since cupric metaborate is blue, the statement is false. The correct reaction would be the reduction of blue cupric metaborate to colorless cuprous metaborate.

3. **Understanding Statement 2**:
- The statement claims that "Cuprous metaborate is obtained by heating boric anhydride and copper sulfate in a non-luminous flame."
- When we heat boric anhydride (B2O3) and copper sulfate (CuSO4), the expected product is cupric metaborate (CuBO2) and sulfur trioxide (SO3), not cuprous metaborate.

4. **Conclusion for Statement 2**:
- The statement is also false because the reaction yields cupric metaborate, not cuprous metaborate.

5. **Final Conclusion**:
- Both statements are false. Therefore, the most appropriate answer is that both statements are incorrect.

### Final Answer:
Both Statement 1 and Statement 2 are false.

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